" 5"2sin^(2)theta+sin theta-1=0

If 0

The general solution of 2 sin^(2)theta - sin theta - 1 = 0 is

If theta in(0,2 pi) and 2sin^(2)theta-5sin theta+2>0 then the range of theta is

The set of values of theta satisfying the inequation 2sin^(2)theta-5sin theta+2>0, when theta in(0,2 pi) is

If 6sin^(2)theta - sin theta = 1 and 0 le theta le pi , what is the value of sin theta ?

sin5theta + sin2theta=0

(b) sin^(2)theta-(1)/(2)sin theta=0

sin4 theta can be written as (a) 4sin theta(1-2sin^(2)theta)sqrt(1-sin^(2)theta)(b)2sin theta cos theta sin^(2)theta(c)4sin theta-6sin^(3)theta(d) None of the above

If 0^(@)angletheta angle20^(@) , then find the value of theta when sin^(2)5theta-sin5theta=0 .