A ball dropped from the top of tower falls first half height of tower in 10 s. The total time spend by ball in air is `["Take "g=10m//s^(2)]`

A stone dropped from the top of a tower travels (5)/(9) th of the height of tower during the last second of fall. Height of the tower is: (Take g = 10 m//s^(2) )

A ball is dropped from the top of a tower.prove that,the height of the tower is 20m if the ball reaches the ground with a velocity 20 m//s .

A particle is dropped from the top of a tower. If it falls half of the height of the tower in its last second of journey, find the time of journey.

A body dropped from top of a tower falls through 40 m during the last two seconds of its fall. The height of tower in m is ( g= 10 m//s^2)