[" 5.If the equation of a given circle is "x^(2)+y^(2)=36" ,then the length of the chord which lies along "],[" he line "3x+4y-15=0" is "]

If the equation of a given circle is x^(2)+y^(2)=36, then the length of the chord which lies along the line 3x+4y-15=0 is 3sqrt(6)2.2sqrt(3)3.6sqrt(3)4 .none of these

If the equation of a given circle is x^2+y^2=36 , then the length of the chord which lies along the line 3x+4y-15=0 is 3sqrt(6) 2. 2sqrt(3) 3. 6sqrt(3) 4. none of these

Let the equation of circle is x ^(2) + y ^(2) - 6x + 4y + 12=0. Then the line 3x - 4y + 5 is a

If y+3x=0 is the equation of a chord of the circle,x^(2)+y^(2)-30x=0, then the equation of the circle with this chord as diameter is:

The equations of two diameters of a circle are x-2y+1=0 and x+y-2=0 and the length of the chord intercepted on the straight line 3x+4y+8=0 by the circle is 6 units. Find the equation of the circle.

The equations of two diameters of a circle are x-2y+1 = 0 and x+y -2 = 0 and the length of the chord intercepted on the straight line 3x + 4y + 8 = 0 by the circle is 6 units. Find the equation of the circle.

Find the equation of the circle , centred at (1,4) , which cuts off of a chord of length 4 units on the line 3x + 4y + 1= 0

If y=2x is the chord of the circle x^(2)+y^(2)-4x=0, find the equation of the circle with this chord as diameter.

y=2x is a chord of the circle x^(2)+y^(2)-10x=0, then the equation of a circle with this chord as diameter is

Find the equation of a circle which passes through the points (1,-2) and (4,-3) and whose centre lies on the line 3x+4y=0