[" QUADRATIC EQUATIONS "],[" 46."(1)/((x-1)(x-2))+(1)/((x-2)(x-3))+(1)/((x-3)(x-4))=(1)/(6)]

Solvef or x,(1)/((x-1)(x-2))+(1)/((x-2)(x-3))+(1)/((x-3)(x-4))=(1)/(6)

Solve for x : (1)/((x-1)(x-2))+(1)/((x-2)(x-3))+(1)/((x-3)(x-4))=(1)/(6)

Solve: 1/((x-1)(x-2))+1/((x-2)(x-3))+1/((x-3)(x-4))=1/6[x!=1,2,3,4]

Solve the following quadratic equations by factorization: (1)/((x-1)(x-2))+(1)/((x-2)(x-3))+(1)/((x-3)(x-4))=(1)/(6)

Solve the following quadratic equations by factorization: 1/((x-1)(x-2))+1/((x-2)(x-3))+1/((x-3)(x-4))=1/6

Solve the following quadratic equation by the method of factorisation:(xxv) 1/((x-1)(x-2))+1/((x-2)(x-3))+1/((x-3)(x-4))=1/6(x!=1,2,3,4)

((2)/(3)x+4)((3)/(2)x+6)-((1)/(7)x-1)((1)/(7)x+1)

(x-1)^4+4(x-1)^3+6(x-1)^2+4 (x-1)+1 = ?

Let x_(1),x_(2), be the roots of the quadratic equation x^(2)+ax+b=0 and x_(3),x_(4), be the roots of the quadratic equation x^(2)-ax+b-2=0. If (1)/(x_(1))+(1)/(x_(2))+(1)/(x_(3))+(1)/(x_(4))=(5)/(6) and x_(1)x_(2)x_(3)x_(4)=24 then find the value of a .