Radiation from hydrogen gas excited to first excited state is used for illuminating certain photoelectric plate . When the radiation from same unknown hydrogen-like gas excited to the same level is used to expose the same plate , it is found that the de Broglie wavelength of the fastest photoelectron has decreased `2.3 time`gt It is given that the energy corresponding to the longest wavelength of the Lyman series of the known gas is `3` times the ionization energy of the hydrogen gas `(13.6 eV)`. Find the work function of photoelectric plate in `eV`. `[Take (2.3)^(2) = 5.25]`

A photoelectric plate is initially exposed to a spectrum of hydrogen gas excited to second energy level. Late when the same photoelectric plate is exposed to a spectrum of some unknown hydrogen like gas, excited to second energy level. It is found that the de-Broglie wavelength of the photoelectrons now ejected has increased sqrt(6.1) times. For this new gas difference of energies of first Lyman line and Balmer series limit is found to be two times the ionization energy of the hydrogen atom is ground state. Detect the atom and determine the work function of the photoelectric plate.

An electron, in a hydrogen like atom , is in excited state. It has a total energy of -3.4 eV, find the de-Broglie wavelength of the electron.

An electron, in a hydrogen like atom , is in excited state. It has a total energy of -3.4 eV, find the de-Broglie wavelength of the electron.

An electron, in a hydrogen like atom , is in excited state. It has a total energy of -3.4 eV , find the de-Broglie wavelength of the electron.

Energy liberated in the de-excitation of hydrogen atom from the third level falls on a photo-cathode. Later when the same photo-cathode is exposed to a spectrum of some unknown - like gas, excited to the second energy level , it is found that the de Broglie wavelength of the fastest photoelectrons now ejected has decreased by a factor of 3 . For this new gas, difference of energies of the second Lyman line and the first balmer line is found to be 3 times the ionization potential of the hydrogen atom. Select the correct statement (s):

Energy liberated in the de-excitation of hydrogen atom from the third level falls on a photo-cathode. Later when the same hoto-cathode is expoced to a spectrum of some unknown - like gas, excited to the second energy level , it is found that the de Broglie wavelength of the fastest photoelectrons now ejected has decreased by a factor of 3 . For this new gas, difference of energies of the second Lyman line and the first balmer line is found to be 3 times the ionization potential of the hydrogen atom. Select the correct statement (s):

If the total energy of anelectron in a hydrogen like atom in excited state is -3.4eV ,then the de Broglie wavelength of the electron is

An electron , in a hydrogen-like atom, is in excited state. It has a total energy of -3.4 eV. Calculate (a) the kinetic energy and (b) the de Broglie wavelength of the electron.