Two particles A and B of mass 1 kg and 2 kg respectively are projected in the direction shown in figure with speeds `u_(A) = 200 ms^(-1)` and `u_(B) = 50 ms^(-1)`. Initially they were 90 m apart. Find the maximum height attained by the center of mass of the particles. Assume acceleration due to gravity to be constant. (Take, `g=10 ms^(-2)`.

Two particles A and B of masses 1kg and 2kg respectively are projected in the directions shown in figure with speeds u_A=200m//s and u_B=50m//s . Initially they were 90m apart. They collide in mid air and stick with each other. Find the maximum height attained by the centre of mass of the particles. Assume acceleration due to gravity to be constant. (g=10m//s^2)

Two particles A and B of masses 1kg and 2kg respectively are projected in the directions shown in figure with speeds u_A=200m//s and u_B=50m//s . Initially they were 90m apart. They collide in mid air and stick with each other. Find the maximum height attained by the centre of mass of the particles. Assume acceleration due to gravity to be constant. (g=10m//s^2)

Two particles A and B masses 1 kg and 2 kg respectivelty are projected in the same vertical line as shown in figure with speeds u_(A) = 200 m//s and u_(B) = 85m//s respectively. Initially they were 90 m apart. Find the maximum height attained by the centre of mass of the system of particles A and B, from the initial position of centre of mass of the system. Assume that none of these particles collides with the ground in that duration Take g = 10 m//s^(2)

Two particles P and Q have mass 1 kg and 2 kg respectively. They are projected along a vertical line with velocity u_(p) = 20 m/s and u_(Q) = 5 m/s when separation between them was 60 m. P was projected vertically up while Q was projected vertically down. Calculate the maximum height attained by the centre of mass of the system of two particles, measured from the initial position of P. Assume that the particles do not collide and that the ground is far below their point of projection [g = 10 m//s^(2)]

Two particles of same mass are project simultaneously with same speed 20ms^(-1) from the top of a tower of height 30m. One is projected vertically upwards and other projected horizontally.The maximum height attained by centre of mass from the ground will be (g=10ms^(-2))