" 16."a^(2)+12a+32

The equation of the axes of the hyperbola 9x^(2) -16y^(2) +72x -32y -16=0 are

I. 12x^(2) + 82 x + 140 = 0 II. 16y^(2) + 48y+ 32 = 0

Let 16 x^(2) - 3y^(2) - 32 x + 12 y = 44 represents a hyperbola . Then _

Show that : 4x^(2) + 16y^(2) - 24x - 32y = 12 is the equation of ellipes , and find its vertices, foci, eccentricity and directrices.

The equation 16x^(2) - 3y^(2) - 32x - 12y - 44 = 0 represents a hyperbola, which one of the following is /are correct

The equation 16x^(2) - 3y^(2) - 32x - 12y - 44 = 0 represents a hyperbola, which one of the following is /are correct

the centre of the hyperbola 9x^(2 )- 16y^(2)+ 72 x - 32y -16=0 is

The eccentricity of the conic 4 x^(2)+16 y^(2)-24 x-32 y=12 is