`y^(cosx)+(tan^(- 1)x)^y=1,f i n d(dy)/(dx)`

If y=btan^(-1)(x/a+tan^(-1) y /x),f i nd (dy)/(dx)dot

If y=x^(tan ^(-1)x) ,then (dy)/(dx)=

y=tan^(- 1)sqrt((1-x)/(1+x))f i n d(dy)/(dx)

y=tan^(- 1)sqrt((1-x)/(1+x))f i n d(dy)/(dx)

If tan(x+y)+tan(x-y)=1, find (dy)/(dx)

If tan(x+y)+tan(x-y)=1 , find (dy)/(dx) .

If y=tan^(-1){(sqrt(1+x)-sqrt(1-x))/(sqrt(1+x)+sqrt(1-x))},"f i n d"(dy)/(dx)

If y=f(cosx)" and "f'(x)=cos^(-1)x," then "(dy)/(dx)=

Solve the differential equation: (i) (1+y^(2))+(x-e^( tan ^(-1)y))(dy)/(dx)=0 (ii) x(dy)/(dx)+cos^(2)y=tan y(dy)/(dx)

If y=sin[2t a n^(-1){sqrt((1-x)/(1+x))}],"f i n d"(dy)/(dx)