An object is projected with a velocity of `20(m)/(s)` making an angle of `45^@` with horizontal. The equation for the trajectory is `h=Ax-Bx^2` where h is height, x is horizontal distance, A and B are constants. The ratio A:B is (g`=ms^-2)`

An object is projected with a velocity of 20 ms^(-1) making an angle of 45^(@) with horizontal. The equation for the trajectory is h = Ax -Bx^2 , where h is height, x is horizontal distance A and B are constants. The ratio A : B is (g = 10 ms^-2)

An object is projected with a velocitiy of 20m//s making an angle of 45^(@) with horizontal. The equation for trajectory is h=Ax-Bx^(2) where h is height x is horizontal distance. A and B are constants. The ratio A.B is x/0.1 . Find value of x.(g=10m//s^(2))

A body is projected with a velocity 20 m*s^(-1) , making an angle of 45^@ with the horizontal. Calculate (ii) horizontal range.