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Prove that: sin36^0s in 72^0s in 108^0s ...

Prove that: `sin36^0s in 72^0s in 108^0s in 144^0=5/(16)dot`

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sin36^(@)sin72^(@)sin108^(@)sin144^(@)=(5)/(16)

sin36^(@)sin72^(@)sin108^(@)sin144^(@)=

sin36^(@)sin72^(@)sin108^(@)sin144^(@)=

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