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If a triangle and a parallelogram are on the same base and between the same parallels, the area of the triangle is equal to half of the parallelogram. GIVEN : `A ABC and ||^(gm)BCDE` on the same base BC and between the same parallels `BC and AD`. TO PROVE : `ar(ABC=1/2 ar(||^(gm)BCDE)` CONSTRUCTION : Draw `AL _|_ BC and DM _|_ bc`, metting BC produced in M.

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