[" If "(y^(2)-5y+3)(x^(2)+x+1)<2x" for all "x in R" ,then the number of possible integral "],[" values of "y" is "],[[" (1) "0," (2) "2],[" (3) Infinite "," (4) "3]]

If (3x-5y)/(3x+5y) = 1/2 . Then find the value of (3x^(2)-5y^(2))/(3x^(2) + 5y^(2)) .

Let (y^2-5y+3)(x^2+x+1)lt2x for all xepsilonR then the interval in which y lies is (A) ((5-sqrt(5))/2,(5+sqrt(5))/2) (B) (-oo,-2] (C) [-2,-2/3] (D) (1,4)

Find each of the following products: (i) (x + 3) (x - 3) (ii) (2x + 5)(2x - 5) (ii) (8 + x)(8 - x) (iv) (7x + 11y) (7x - 11y) (v) (5x^(2) + (3)/(4) y^(2)) (5x^(2) - (3)/(4) y^(2)) (vi) ((4x)/(5) - (5y)/(3)) ((4x)/(5) + (5y)/(3)) (vii) (x + (1)/(x)) (x - (1)/(x)) (viii) ((1)/(x) + (1)/(y)) ((1)/(x) - (1)/(y)) (ix) (2a + (3)/(b)) (2a - (3)/(b))

Evaluate x and y if [(x,2),(-3,y)]=2[(x^(2),1),(-(3)/(2),3y-5)] .

If the points (x_(1),y_(1)),(x_(2),y_(2)), and (x_(3),y_(3)) are collinear show that (y_(2)-y_(3))/(x_(2)x_(3))+(y_(3)-y_(1))/(x_(3)x_(1))+(y_(1)-y_(2))/(x_(1)x_(2))=0

{:("Column" A ,, "Column" B), (225x^(2) - 625 y^(2) = ,, (a) 25(x-2) (x-2)), (x^(2) - x - y - y^(2) = ,, (b) 25(3x- 5y) (3x + 5y)), (x^(2) - x - y^(2) + y = ,, (x + y) (x - y- 1)), (25x^(2) - 100 x + 100 = ,, (d) (x - y) (x + y -1)), (,,(e) (x + y) (x + y - 1)):}

Solve for (x - 1)^(2) and (y + 3)^(2) , 2x^(2) - 5y^(2) - x - 27y - 26 = 3(x + y + 5) and 4x^(2) - 3y^(2) - 2xy + 2x - 32y - 16 = (x - y + 4)^(2) .

x^(3)+3x^(2)y+xy^(2)-5y^(3)=0 then ((d^(2)y)/(dx^(2)))_(1,1) is