A potentiometer wire has resistance `40Omega` and its length is 10m. It is connected by a resistance of `760Omega` in series if emf of battery is 2V then potential gradient is:-

A potentiometer wire has a length 2 m and resistance of 10 Omega . It is coonnected in series with a resistance of 990 Omega and a cell of e.m.f. 2 V. The potential gradient along the wire is

A potentiometer wire has a length of 2m and resistance 10Omega . It is connected in series with resistance 990Omega and a cell of emf 2V. Calculate the potential gradient along the wire.

A potentiometer wire of length 10m and resistance 20Omega is connected in series with another resistance of 80Omega and a battery of emf 4V . The potential gradient on the wire will be (in mV//cm )

A potentiometer wire 10m long has a resistance of 40Omega . It is connected in series with a resistances box and a 2 v storage cell. If the potential gradient along the wire is 0.01(V)/(m) the resistance unplugged in the box is

A potentiometer wire 10 long has a resistance of 40Omega . It is connected in series with a resistances box and a 2 v storage cell. If the potential gradient along the wire is 0.01(V)/(m) the resistance unplugged in the box is

A potentiometer wire has a resistance of 20 Omega and length 10 m. It is connected in series with a battery of emf 2.5 V and negligible internal resistance, and an external resistance of 5 Omega . Fall of potential in mV per metre is

If a ideal battery of e.m.f.10 V is connected with external resistance 9Omega and a wire of length 10 m and resistance 1Omega in series as shown. Then the potential gradient of wire is