[" 19."mx-ny=m^(2)+n^(2)],[x+y=2m.quad [CBSE2006C]]

Solve for x and y : mx- ny = m^(2) + n^(2) " " x - y = 2n

Solve the following system of equations by method of cross-multiplication: mx-ny=m^(2)+n^(2),quad x+y=2m

Prove : int sin mx sin n x dx[ m^(2) != n^(2)] , = 1/2 [ (sin(m-n)x)/(m-n) - (sin (m+n)x)/(m+n) ] + c

solve the following pair using cross multiplication method mx+ny=m^(2)+n^(2) and x+y=2m

If y=mx+1 and y^(2)=4x+1 then m=

If the each of algebraic expressions lx^(2) + mx + n, mx^(2) + nx + l and nx^(2) + lx + m are prefect squares, then (l +m)/(n) = _____

Number of integral values of m for which lines x+y+1=0,mx-m^(2)y+3=0 and 2mx-(2m-1)y+(3m+2)=0 are concurrent

If the are between y =mx^(2) and x= my^(2) (m gt 0 ) is (1)/(4) sq . Unit then the value of m is:

If y=ae^(mx)+be^(-mx) , then (d^2y)/dx^2-m^2y is equals to (a). m^2(ae^(mx)-be^(mx)) (b).1 (c).0 (d).None of these