" (ii) Find area of the ellipse "(x^(2))/(a^(2))+(y^(2))/(b^(2))=1" using integral method."

The area of the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 is

The area of the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 is

The area of the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 is

Find the area of the ellipse (x^2 )/(a^2) + (y^2)/(b^2)=1 (a gt b) .

Find the area of the ellipse (x^(2))/(a^(2))+ (y^(2))/(b^(2))=1 by the method of integration.

If the area of the ellipse ((x^(2))/(a^(2)))+((y^(2))/(b^(2)))=1 is 4 pi, then find the maximum area of rectangle inscribed in the ellipse.

(1) Draw the rough sketch of the ellipse (x^(2))/(a^(2)) + (y^(2))/(b^(2)) = 1 . Find the area enclosed by the ellipse (x^(2))/(a^(2)) + (y^(2))/(b^(2)) = 1 .

Find the area of ellipse x^(2)/1 + y^(2)/4 = 1.