`sin 3 alpha = 4 sin alpha sin(x + alpha) sin(x-alpha)`

If sin 3alpha = 4 sin alpha sin (x + alpha)sin(x-alpha) , then x =

sin3alpha = 4 sin alpha sin(x+alpha)sin(x-alpha)

sin3 alpha=4sin alpha sin(x+alpha)sin(x-alpha)

Solve sin 3alpha=4 sin alpha sin (x+alpha)sin(x-alpha) where alpha=n pi,n in Z .

Solve: sin3 alpha=4sin alpha sin(x+alpha)sin(x-alpha), where alpha!=n pi,n in Z

The set of values of x satisfying the equation sin3 alpha=4sin alpha sin(x+alpha)sin(x-alpha) is n pi+-(pi)/(4),AA n in Zn pi+-(pi)/(3),AA n in Zn pi+-(pi)/(9),AA n in Zn pi+-(pi)/(12),AA n in Z

The number of solutions of the equation sin3 alpha=4sin alpha*sin(x+alpha)*sin(x-alpha) where 0

( sin alpha sin 3alpha + sin 3alpha sin 7 alpha + sin 5 alpha sin 15 alpha )/( sin alpha cos 3 alpha + sin 3alpha cos 7 alpha + sin 5 alpha cos 15 alpha ) =

Find the general solution for each of the following equations : sin3alpha=4sinalphasin(x+alpha)sin(x-alpha)