`(x^4+x^2+1)/(x^2-4x-5)<0`

If x≠ − 1 , 2 and 5, then the simplified value of {(2(x^3 -8))/(x^2-x -2) xx (x^2+ 2x +1)/(x^2 -4x-5) ÷ (x^2 +2x+4)/(3x-15)} is equal to: यदि x≠ − 1 , 2 और 5 है तो {(2(x^3 -8))/(x^2-x -2) xx (x^2+ 2x +1)/(x^2 -4x-5) ÷ (x^2 +2x+4)/(3x-15)} का सरलीकृत मान बराबर हैः

If x ne -1,2 and 5, then the simplified value of {(2(x^3-8))/(x^2-x-2)xx (x^2+2x+1)/(x^2-4x-5)} div (x^2+2x+4)/(3x-15) is equal to : यदि x ne -1,2 और 5 है, तो {(2(x^3-8))/(x^2-x-2)xx (x^2+2x+1)/(x^2-4x-5)} div (x^2+2x+4)/(3x-15) का सरलीकृत मान क्या होगा ?

If P= (x^4-8x)/(x^3-x^2-2x), Q= (x^2+2x+1)/(x^2-4x-5) and R=(2x^2+4x+8)/(x-5) , then (PxxQ) div R is equal to: यदि P= (x^4-8x)/(x^3-x^2-2x), Q= (x^2+2x+1)/(x^2-4x-5) तथा R=(2x^2+4x+8)/(x-5) है, तो (PxxQ) div R का मान किसके बराबर है ?

The value of int_(0)^(2)((x^(2)-2x+4)sin(x-1))/(2x^(2)-4x+5)dx is equal to

int (2x+1)/(x^2+4x-5) dx

1/(x^2-3x+2)+1/(x^2-5x+6)+1/(x^2-4x+3)

int(dx)/((x^(2)+4x+5)^(2)) is equal to (1)/(2)[tan^(-1)(x+1)+(x+2)/(x^(2)+4x+5)]+c(1)/(2)[tan^(-1)(x+2)-(x+2)/(x^(2)+4x+5)]+c(1)/(2)[tan^(-1)(x+1)-(x+2)/(x^(2)+4x+5)]+c(1)/(2)[tan^(-1)(x+1)+(x+2)/(x^(2)+4x+5)]+c