Energy of an electron in an excited hydrogen atom is `-3.4eV`. Its angualr momentum will be: `h = 6.626 xx 10^(-34) J-s`.

The energy of an electron in hydrogen atom is -3.4 eV, then its angular momentum is ......

The energy of an excited hydrogen atom is -0.85 eV . Find the angular momentum of the electron. (h = 6.63 xx 10^(-34) J.s., pi = 3.142, E_(1) = -13.6 eV)

The energy of electron in an excited hydrogen atom is -3.4eV . Its angular momentum according to bohr's theory will be

The energy of electron in an excited hydrogen atom is -3.4eV . Its angular momentum according to bohr's theory will be

The energy of an excited hydrogen atom is 0.38 eV. Its angular momentum is n . h/(2pi) . Find n

The energy of an excited hydrogen atom is 0.38 eV. Its angular momentum is n . h/(2pi) . Find n

The energy of an electron in an excited state of hydrogen atom is -3.4 eV . The angular momentum of the electron in this state is

The energy of an electron in an excited hydrogen atom is -3.4 eV . Calculate the angular momentum of the electron according to Bohr's theory. (Given Rydberg's constant R=1.09737 xx 10^-7 m^-1, h=6.626176 xx 10^-34 Js, c=3 xx 10^8 ms^-1) .