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[" (ji) "cot theta+cosec thetaquad (1)/(...

[" (ji) "cot theta+cosec thetaquad (1)/(tan theta+cot theta)],[" ufiv "(cosec theta-sin theta)(sec theta-cos theta)=(cos v)/(tan theta+cos theta)]

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Find ("cosec" theta-sin theta)(sec theta-cos theta)(tan theta+cot theta) :?

csc theta(1+cos theta)(csc theta-cot theta)=1

(cosec theta -sin theta ) (sec theta - cos theta ) (tan theta + cot theta ) = 1.

("cosec " theta - sin theta ) ( sec theta - cos theta ) ( tan theta + cot theta ) =

(sec theta+csc theta)^(2)-(tan theta+cot theta)^(2)=

(cosec theta+sin theta)(cosec theta-sin theta)=cot^(2)theta+cos^(2)theta

(cosec theta + sin theta) (sec theta - cos theta) tan theta + cot theta) is equal to

(cot theta+csc theta-1)/(cot theta-csc theta+1)=(1+cos theta)/(sin theta)

Prove that (cos theta-sin theta+1)/(cos theta+sin theta-1)=csc theta+cot theta