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Prove that the resultant of two vector o...

Prove that the resultant of two vector of equal magnitude is equal to either vector if the angle between the two vector is `120^(@)`

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To prove that the resultant of two vectors of equal magnitude is equal to either vector when the angle between them is \(120^\circ\), we can follow these steps: ### Step 1: Define the Vectors Let the two vectors be \( \vec{A} \) and \( \vec{B} \), both having the same magnitude \( p \). The angle between them is given as \( \theta = 120^\circ \). ### Step 2: Use the Law of Cosines The magnitude of the resultant vector \( \vec{R} \) can be calculated using the formula: \[ ...
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Knowledge Check

  • Resultant of two vector of equal magnitude A is

    A
    `sqrt(3)Aat 60^(@)`
    B
    `sqrt(2)Aat 90^(@)`
    C
    `2Aat 120^(@)`
    D
    `Aat 180^(@)`
  • The resultant of two vectors of same magnitude is equal to the magnitude of one of the vectors, then the angle between them is

    A
    `30^(@)`
    B
    `60^(@)`
    C
    `90^(@)`
    D
    `120^(@)`
  • The resultant of two vectors of magnitudes 3 units and 5 units is perpendicular to 3 units.The angle between the vectors is

    A
    `127^(@)`
    B
    `120^(@)`
    C
    `75^(@)`
    D
    `150^(@)`
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