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If the magnitude of two vectors are 3 ...

If the magnitude of two vectors are ` 3 ` and `6` and ther scalar product is `9`, find the angle between the two vectors.

Text Solution

Verified by Experts

Angle between the two vectors is
`cos theta (vecA. vecB)/(|vecA||vecB|)=(9)/(6xx3)=(9)/(18)=(1)/(2)`
`rArr theta =60^(@)`
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