A particle is thrown horizontally from the top of an inclined plane , with a speed of `5 m//s` . If the inclination of the plane is `30^(@)` with the horizontal , how far from the point of projection will the particle strike the plane ?

Explanation

To solve the problem of finding how far from the point of projection the particle will strike the inclined plane, we can follow these steps:

### Step 1: Understand the Geometry of the Problem
We have an inclined plane at an angle of \(30^\circ\) with the horizontal. A particle is thrown horizontally with a speed of \(5 \, \text{m/s}\) from the top of this incline. We need to determine the horizontal distance \(d\) from the point of projection where the particle strikes the plane.

### Step 2: Set Up the Coordinate System
Let’s denote:
- \(x\) as the horizontal distance traveled by the particle,
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