A body A is moving along a straight path with a velocity of `4m//s` Another body B is moving with a velocity of `5m//s`, on a traight path, at an angle of `45^(@)` to the path of A. Calculate the spend of B relative to A.

Explanation

To find the speed of body B relative to body A, we can follow these steps:

### Step 1: Identify the velocities
- Velocity of body A, \( V_A = 4 \, \text{m/s} \) (along the x-axis).
- Velocity of body B, \( V_B = 5 \, \text{m/s} \) at an angle of \( 45^\circ \) to the path of A.

### Step 2: Resolve the velocity of B into components
Since body B is moving at an angle of \( 45^\circ \), we can resolve its velocity into horizontal (x) and vertical (y) components:
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