An aircraft is flying at a height of `3400m ` above the ground . If the angle subtended at a ground observation point by the aircreaft positions 10.0 s apart is `30^(@)` , what is the speed of the aircraft ?

Explanation

Let A and B be the positions of the aircraft for which ` angle ACB=30^(@)`
Time taken by the aircraft to go from A to B =10 s
Here OC =3400 m
`tan 15^(@)=(OA)/(OC)`
`rArr OA=OC tan 15^(@)`
`=3400xx0.267=907.8m`
Speed of aircraft` =("Distance "AB)/("Time")`
`=(2xxOA)/(10 s)=(2xx907.8)/(10)`
`=181.56`m