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A particle is given an initial velocity ...

A particle is given an initial velocity of `vecu=(3 hati+4 hatj) m//s`. Acceleration of the particle is `veca=(3t^(2) +2 thatj) m//s^(2) `. Find the velocity of particle at t=2s.

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To find the velocity of the particle at \( t = 2 \) seconds, we will follow these steps: ### Step 1: Write down the given information - Initial velocity: \[ \vec{u} = 3 \hat{i} + 4 \hat{j} \, \text{m/s} \] - Acceleration: ...
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Knowledge Check

  • If velocity of a particle is given by v=2t^(2)-2 then find the acceleration of particle at t = 2 s.

    A
    0
    B
    2
    C
    4
    D
    8

  • If displacement of particle is s=(t^(3))/(3)-(t^(2))/(2)-(t)/(2)+6 , then velocity of the particle at t=4 sec. is

    A
    11.5 units/sec
    B
    14.5 units/sec
    C
    19.5 units/sec
    D
    16.5 units/sec

  • A particle has an initial velocity of 4 hati +3 hatj and an acceleration of 0.4 hati + 0.3 hatj . Its speed after 10s is

    A
    10 units
    B
    7 units
    C
    `7 sqrt(2)` units
    D
    8.5 units