Home
Class 11
PHYSICS
If a force of (8.0 hati+2.0 hatj+3 hatk)...

If a force of `(8.0 hati+2.0 hatj+3 hatk)N` displaces a body through a distance of `(6.0 hati-3 .0 hatj -9 hatk)`m . The work done will be

A

15 J

B

34 J

C

56 J

D

42 J

Text Solution

AI Generated Solution

The correct Answer is:
To find the work done by a force when a body is displaced, we can use the formula for work done, which is given by the dot product of the force vector and the displacement vector. ### Step-by-Step Solution: 1. **Identify the Force and Displacement Vectors:** - The force vector \( \mathbf{F} \) is given as: \[ \mathbf{F} = 8 \hat{i} + 2 \hat{j} + 3 \hat{k} \, \text{N} \] - The displacement vector \( \mathbf{d} \) is given as: \[ \mathbf{d} = 6 \hat{i} - 3 \hat{j} - 9 \hat{k} \, \text{m} \] 2. **Calculate the Dot Product:** - The work done \( W \) is calculated using the dot product: \[ W = \mathbf{F} \cdot \mathbf{d} \] - The dot product is calculated as follows: \[ W = (8 \hat{i} + 2 \hat{j} + 3 \hat{k}) \cdot (6 \hat{i} - 3 \hat{j} - 9 \hat{k}) \] 3. **Expand the Dot Product:** - Using the properties of dot product: \[ W = (8 \cdot 6) + (2 \cdot -3) + (3 \cdot -9) \] - Calculate each term: - \( 8 \cdot 6 = 48 \) - \( 2 \cdot -3 = -6 \) - \( 3 \cdot -9 = -27 \) 4. **Sum the Results:** - Combine the results: \[ W = 48 - 6 - 27 \] - Calculate: \[ W = 48 - 6 = 42 \] \[ W = 42 - 27 = 15 \, \text{J} \] 5. **Final Answer:** - The work done is: \[ W = 15 \, \text{J} \]

To find the work done by a force when a body is displaced, we can use the formula for work done, which is given by the dot product of the force vector and the displacement vector. ### Step-by-Step Solution: 1. **Identify the Force and Displacement Vectors:** - The force vector \( \mathbf{F} \) is given as: \[ \mathbf{F} = 8 \hat{i} + 2 \hat{j} + 3 \hat{k} \, \text{N} ...
Promotional Banner

Topper's Solved these Questions

  • MOTION IN A PLANE

    MODERN PUBLICATION|Exercise Revision Exercises (Fill in the Blanks)|9 Videos
  • MOTION IN A PLANE

    MODERN PUBLICATION|Exercise Revision Exercises (Short Answer Question)|31 Videos
  • MOTION IN A PLANE

    MODERN PUBLICATION|Exercise Revision Exercises (very Short Answer Questions)|46 Videos
  • MECHANICAL PROPERTIES OF FLUIDS

    MODERN PUBLICATION|Exercise Chapter Practise Test|16 Videos
  • MOTION IN A STRAIGHT LINE

    MODERN PUBLICATION|Exercise CHAPTER PRACTICE TEST|16 Videos

Similar Questions

Explore conceptually related problems

A force (3hati+2hatj) N displaces an object through a distance (2hati-3hatj) m. The work done is :

A force vecF = (5 hati + 4 hatj)N acts on a body and produces a displacement vecs = (6 hati - 5 hatj + 3 hatk)m . The work done will be

When a force vector vecF=(hati+2hatj+hatk) N acts on a body and produces a displacement of vecS=(4hati+hatj+7hatk) m, then the work done is

A force vecF=(5hati+4hatj)N acts on a body and produces a displacement vecS=(6hati-5hatj+3hatk) m. The work done will be

A force of 2 hati + 3 hatj + 4 hatk N acts on a body for 4 second and producesa displacement of (3 hati + 4 hatj + 5 hatk)m . The power used is

Under a force of 10 hati - 3 hatj +6 hatk newton, a body of mass 5 kg is displaced from the position 6 hati + 5 hatj - 3 hatk to the position 10 hati - 2hatj + 7 hatk . Calculate the work done.