If `|veca+vecb|=|vecas-vecb|, (veca,vecb!=vec0)` show that the vectors `veca and vecb` are perpendicular to each other.

Explanation

`|vecA+vecB|=||vecA-vecb|`
`|vecA+vecB|^(2)=|vecA-vecB|^(2)`
`A^(2)+B^(2)+2AB cos theta =A^(2) +B^(3)-2AB cos theta`.
`4AB cos theta =0`
As `Ane 0, Bne0 or cos theta =0`
`rArr theta =90^(@)`