The angle of projection at which the horizontal range and maximum height of projectile are equal is

Explanation

Horizontal range =`(u^(2) sin 2 theta)/(g)`
Maximum height attained `=(u^(2) sin ^(2) theta)/(2g)`
`(u^(2) sin 2 theta)/(g)=(u^(2) sin ^(2) theta)/(2g)`
`(u^(2)2 sin theta cos theta)/(g)=(u^(2) sin theta sin theta)/(2g)`
`4=tan theta`
`theta=tan^(-1)(4)`