For which angle of projection the horizontal range is 5 times the maximum height attrained ?

Explanation

To solve the problem of finding the angle of projection for which the horizontal range is 5 times the maximum height attained, we can follow these steps:

### Step 1: Understand the formulas
The horizontal range \( R \) and maximum height \( H \) for a projectile launched with an initial velocity \( u \) at an angle \( \theta \) are given by the following formulas:
- Horizontal Range:
\[ R = \frac{u^2 \sin 2\theta}{g} \]
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