Find the equation of trajectory, time of flight , maximum height and horizontal range of a projectile when projected at an angle `theta` with the vertical direction .

At a height of 45 m from ground velocity of a projectile is, v = (30hati + 40hatj) m//s Find initial velocity, time of flight, maximum height and horizontal range of this projectile. Here hati and hatj are the unit vectors in horizontal and vertical directions.

Find (a) time of flight , (b) Max.height (c ) Horizontal range of projectile projected with speed (v) making an angle theta with the horizontal direction from ground.

Define trajectory of a projectile and hence derive equation of motion of the projectile when projected at an angle theta with horizontal direction.

Find (i) the time of flight (ii) maximum height and (iii) horizontal of a projectile given angular projection on an inclined plane where angle of inclination with horizontal is theta_0 .

Prove that the time of flight T and the horizontal range R of a projectile are connected by the equation: gT^2 =2 R tan theta , where theta is the angle of projection.

The horizontal range of a projectile is 2 sqrt(3) times its maximum height. Find the angle of projection.

For a projectile projected at an angle _____the maximum height and horizontal range are equal.

The horizontal range is four times the maximum height attained by a projectile. The angle of projection is