An aeroplane takes off at an angle of `60^(@)` to the vertical .If the component of velocity along the vertical is `250km//hr`, calculate its
(i) actual velocity and
(ii) horizontal component of velocity.

Explanation

To solve the problem step by step, we will break it down into two parts as per the question.

### Given:
- Angle of takeoff with the vertical, \( \theta = 60^\circ \)
- Vertical component of velocity, \( V_y = 250 \, \text{km/hr} \)

### Part (i): Calculate the Actual Velocity

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