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The resultant of vectors vecA=3hati+4hat...

The resultant of vectors `vecA=3hati+4hatj+5hatk and vecB =5hati+3 hatj+4hatk` makes an angle `theta` with the X-axis . Evaluate `cos theta`.

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To solve the problem of finding \( \cos \theta \) for the resultant vector of \( \vec{A} \) and \( \vec{B} \), we will follow these steps: ### Step 1: Write down the vectors Given: \[ \vec{A} = 3\hat{i} + 4\hat{j} + 5\hat{k} \] \[ ...
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MODERN PUBLICATION-MOTION IN A PLANE -Revision Exercises (Numerical Problems)
  1. For the vector vecA=a hati+2hatj-hatj and vecB =2ahati-ahatj+4hatk to ...

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  2. Under the effect of a force vecF=5hati-2 hatj+3hatkN, abody of mass 1 ...

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  3. For three vectors , vecX, vecY and vecZ, vecZ=vecX+vecY and |vecX|=12,...

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  4. The resultant of vectors vecA=3hati+4hatj+5hatk and vecB =5hati+3 hatj...

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  5. For vectors vecA=3hati-4hatj+5hatk and vecB=hati-hatj-hatk, calculate ...

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  6. Determine the value of alpha for which the vectors i-3alphahatj+hatk a...

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  7. Determine a unit vector perpendicular to both the vectors vecA=2hati-3...

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  8. The magnitude of two vectors vecA and vecB is 3 and 4 respectively . ...

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  9. Find the area of the triangle determined by two vectors: vecA=hati-3ha...

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  10. The diagonals of a parallelogram are given by -3hati+2hatj-4hatk and -...

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  11. The position vector of a particle is given by vecr=(2 sin 2t)hati+(3+ ...

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  12. From the top of a hill 480 m high , a projectile is fired horizontally...

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  13. A body is projected horizontally with a velocity of 39.4m//s from the ...

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  14. Two hills of height 100 m and 80 m have a valley of breadth 15 between...

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  15. A particle is projected with a velocity of 25 m//s at an angle of 30^...

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  16. Find the angle of projection of a projectile for which the horizontal ...

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  17. A batman hits a cricket ball with a speed of 25 m//s at a projection a...

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  18. From the top of a cliff of height 150 m, a stone is thrown up with a ...

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  19. Calculate the angular speed of againt wheel of radius 10 m, moving wi...

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  20. Moon takes 27.3 days to complete one revolution around the earth , in ...

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