From the top of a hill 480 m high , a projectile is fired horizontally with a speed of `96 m//s` . Calculate
(i) the time taken by projectile to reach the ground .
(ii) the distance of the target from the hill .
(iii) the velocity with which the projectile hits the ground . Take `g=10ms^(-2)`

Explanation

To solve the problem step by step, we will break it down into three parts as per the question.

### Given:
- Height of the hill, \( h = 480 \, \text{m} \)
- Horizontal speed of the projectile, \( u = 96 \, \text{m/s} \)
- Acceleration due to gravity, \( g = 10 \, \text{m/s}^2 \)

### (i) Time taken by the projectile to reach the ground
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