A particle is projected with a velocity of `25 m//s` at an angle of `30^(@)` with the horizontal . Calculate
(i) The maximum height ,
(ii) time of flight and
(iii) horizontal range .

Explanation

To solve the problem of a particle projected with a velocity of \(25 \, \text{m/s}\) at an angle of \(30^\circ\) with the horizontal, we will calculate the maximum height, time of flight, and horizontal range step by step.

### Given:
- Initial velocity, \(u = 25 \, \text{m/s}\)
- Angle of projection, \(\theta = 30^\circ\)
- Acceleration due to gravity, \(g = 10 \, \text{m/s}^2\)

### (i) Maximum Height (H)
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