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The maximum horizontal range of a projec...

The maximum horizontal range of a projectile is 400 m . The maximum value of height attained by it will be

A

`100m`

B

`200m`

C

`400m`

D

`800 m`

Text Solution

Verified by Experts

The correct Answer is:
B
(b): `R_("max")=400m`
`(u^(2))/(g)=400m rArr (u^(2))/(g)=400m`
Maximum Height, `H=(u^(2) sin ^(2) theta)/(2g)=(u^(2))/(2g)(sin 90^(@))^(2)`
`=(1)/(2) (400m)`
`=200m`
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