The equations of motion of a projectile are given by `x=36tm` and `2y=96t-9.8t^(2)m` .The angle of projection is

Options

A. `sin^(-1) ((4)/(5))`
B. `sin^(-1)((5)/(4))`
C. `sin^(-1)((4)/(3))`
D. `sin ^(-1)((3)/(4))`

Answer

A

Explanation

(a): `36 t=x`
`t=(x)/(36)`
`2y=96 t-9.8 t`
`y=(96xx x)/(2xx36)-(9.8x^(2))/(36xx36xx2)`
Compare with equation,
`y=x tan theta -(g)/(2u^(2) cos ^(2)theta)x^(2)`

`tan theta=(96)/(2xx36)`,
`tan theta=(480)/(36)`
`tan theta=(4)/(3)`
`sin theta =(4)/(3)`
`theta =sin^(-1)((4)/(5))`