The horizontal range and the maximum height of a projectile are equal. The angle of projection of the projectile is

Options

A. `theta =45`
B. `theta=tan^(-1)((1)/(4))`
C. `theta=tan^(-1)(4)`
D. `theta=tan^(-1)(2)`

Answer

C

Explanation

(c): Given, `R=H`
`(u^(2) sin 2theta)/(g) =(u^(2) sin ^(2) theta)/(2g)`
`2 sin theta. Cos theta =(sin ^(2) theta)/(2)`
`tan theta =4 rArr =tan ^(-1) (4)`