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A particle is moving with velocity vecv...

A particle is moving with velocity ` vecv = k( y hat(i) + x hat(j)) `, where `k` is a constant . The genergal equation for its path is

A

`y=x^(2)+` constant

B

`y^(2)=x+` constant

C

`xy=` constant

D

`y^(2)=x^(2)+` constant

Text Solution

Verified by Experts

The correct Answer is:
D
(d): `vecv=K((dx)/(dt)hati+(dy)/(dt)hatj)`
On comparison , `(dx)/(dt)=y, (dy)/(dt)=x`
`(dx)/(dy)=(y)/(x)rArr y^(2)=x^(2)+` constant
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