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A projectile is given an initial velocit...

A projectile is given an initial velocity of ` ( hat(i) + 2 hat (j) ) m//s`, where ` hat(i)` is along the ground and `hat (j)` is along the vertical . If ` g = 10 m//s^(2) `, the equation of its trajectory is :

A

`y=2x-5x^(2)`

B

`4y=2x-5x^(2)`

C

`4y=2x-25x^(2)`

D

`y=x-5x^(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
(a): `vecu=hati+2hatj`,
`v_(x)=1 and v_(y)=2`
`a_(x)=0 and a_(y)= - 10`
`S_(x)=u_(x)t+(1)/(2) a_(x)t^(2) rArr x=1xxt`
`rArr t=x`
`S_(y)=u_(y)t+(1)/(2)a_(y)t^(2)`
`rArr y=2t-5t^(2)`
Substituting from equation (i)
`y=2x-5x^(2)`
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