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Particle A is projected with speed u at...

Particle A is projected with speed u at an angle `theta` with the horizontal . Another particle B is also projected with same speed u at an angle `90-theta` with the horizontal . Both the projectiles are fired from the ground and reaches the ground after completing the projectile . Time of flight for A is `t_(A)` and that for B it is `t_(B)`. Range of the projectile A is `R_(A)` and that for B is `R_(B)` . Maximum height reached by the projectile A is `h_(A)` and that for B is `h_(B)`

A

`{:(P,Q,R,S),(2,3,4,1):}`

B

`{:(P,Q,R,S),(1,2,3,4):}`

C

`{:(P,Q,R,S),(2,4,1,3):}`

D

`{:(P,Q,R,S),(4,2,3,1):}`

Text Solution

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The correct Answer is:
a
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Knowledge Check

  • A projectile is projected with a speed u at an angle theta with the horizontal. What is the speed when its direction of motion makes an angle theta//2 with the horizontal

    A
    `(u cos theta)/(2)`
    B
    `u cos theta`
    C
    `u (2 cos (theta)/(2) - sec (theta)/(2))`
    D
    `u (cos(theta)/(2) - sec(theta)/(2))`

  • A particle is fired from a point on the ground with speed u making an angle theta with the horizontal.Then

    A
    the radius of curvature of the projectile at the highest point is `(u^(2)cos^(2) theta)/g`
    B
    the radius of curvature of the projectile at the highest point is `(u^(2)sin^(2) theta)/g`
    C
    at the point of projection magnitude of tangential acceleration is `g sin theta`
    D
    at the point of projection magnitude of tangential acceleration is `g cos theta`

  • A particle is projected with a speed u at an angle theta with the horizontal. What will be the speed of the particle when direction of motion of particle is at an angle alpha with the horizontal?

    A
    `u cos theta sec alpha`
    B
    `u sec theta cos alpha`
    C
    `u cos theta tan alpha`
    D
    `u cos theta cot alpha`