Home
Class 11
PHYSICS
A particle is projected from the top of ...

A particle is projected from the top of a tower of height h with a speed u at an angle `theta` above the horizontal .
`T_(1)`=Time taken by the projectile to reach the height of tower again .
`T_(2)`=Time taken by the projectile to move at right angle to initial direction of motion .
`V_(1)`=Speed of the projectile when it moves at an angle `theta//2` with the horizontal .
`V_(2)`=Speed with projectile strikes the ground .
.

A

`{:(P,Q,R,S),(4,1,2,3):}`

B

`{:(P,Q,R,S),(1,2,3,4):}`

C

`{:(P,Q,R,S),(2,4,1,3):}`

D

`{:(P,Q,R,S),(2,1,3,4):}`

Text Solution

Verified by Experts

The correct Answer is:
a
Promotional Banner

Topper's Solved these Questions

  • MOTION IN A PLANE

    MODERN PUBLICATION|Exercise COMPETITION FILE OBJECTIVE TYPE QUESTIONS (MATRIX MATCH TYPE QUESTIONS)|1 Videos
  • MOTION IN A PLANE

    MODERN PUBLICATION|Exercise COMPETITION FILE OBJECTIVE TYPE QUESTIONS (INTEGER TYPE QUESTIONS)|10 Videos
  • MOTION IN A PLANE

    MODERN PUBLICATION|Exercise COMPETITION FILE OBJECTIVE TYPE QUESTIONS (Assertion Reason Type Questions)|10 Videos
  • MECHANICAL PROPERTIES OF FLUIDS

    MODERN PUBLICATION|Exercise Chapter Practise Test|16 Videos
  • MOTION IN A STRAIGHT LINE

    MODERN PUBLICATION|Exercise CHAPTER PRACTICE TEST|16 Videos

Similar Questions

Explore conceptually related problems

For a projectile first with velocity u at an angle theta with the horizontal.

Define trajectory of a projectile and hence derive equation of motion of the projectile when projected at an angle theta with horizontal direction.

A projectile is projected with speed u at an angle theta with the horizontal . The average velocity of the projectile between the instants it crosses the same level is

A particle is projected at time t=0 from a point O with a speed u at an angle theta to horizontal. Find the torque of a gravitational force on projectile about the origin at time t. (x,y plane is vertical plane)

A particle is projected from the top of a tower of height H. Initial velocity of projection is u at an angle theta above the horizontal . Particle hits the ground at a distance R from the bottom of tower. What should be the angle of projection theta so that R is maximum ? What is the maximum value of R?

A projectile is fired with a velocity v at right angle to the slope inclined at an angle theta with the horizontal. The range of the projectile along the inclined plane is

A particle is projected in air with an initial velocity u directed at an angle theta above horizontal. After time t_(0) the velocity of the particle is directed at angle phi above horizontal.

A projectile is projected with a speed u at an angle theta with the horizontal. What is the speed when its direction of motion makes an angle theta//2 with the horizontal

A particle of mass m is projected with an initial velocity U at an angle theta to the horizontal. The torque of gravity on projectile at maximum height about the point of projection is