A charged particle is inside a magnetic field `vecB = (10hati - 6hatj) xx 10^(-4) T`. The acceleration of the charged particle is given by `veca = 3hati + xhatj m//s^(2)`. What should be the value of x for this to be possible?

Explanation

To solve the problem, we need to find the value of \( x \) such that the acceleration of a charged particle in a magnetic field is consistent with the Lorentz force law. Here’s a step-by-step solution:

### Step 1: Identify the Given Quantities
We have the magnetic field:
\[ \vec{B} = (10 \hat{i} - 6 \hat{j}) \times 10^{-4} \, \text{T} \]
And the acceleration of the charged particle:
...