A neutron and a proton both are fired with some speed of `3 xx 10^(6)` m/s perpendicular to a uniform magnetic field of 1 T. What will be the individual acceleration of particles! Consider that only magnetic force is acting on the particles.

Explanation

To find the individual acceleration of a neutron and a proton when fired perpendicular to a magnetic field, we will follow these steps:

### Step 1: Understand the Forces Acting on the Particles
When charged particles move in a magnetic field, they experience a magnetic force given by the Lorentz force equation:
\[ F = q(\mathbf{v} \times \mathbf{B}) \]
where:
- \( F \) is the magnetic force,
- \( q \) is the charge of the particle,
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