Two types of particles having same charge equal to `+2e` but different masses are moving with a constant velocity of `6 xx 10^(4)` m/s in the form of a beam. These particles suddenly encounter a perpendicular magnetic field in a rectangular region having intensity equal to `0.5` T. It is found that particles emerge from the field in the backward direction from two different points. These points are at a distance 3 cm and `3.5` cm from the incident beam. Find the ratio of their masses.

Explanation

To solve the problem of finding the ratio of the masses of two particles with the same charge moving in a magnetic field, we will follow these steps:

### Step 1: Write down the given data
- Charge of the particles, \( q = +2e = 2 \times 1.6 \times 10^{-19} \, \text{C} \)
- Magnetic field intensity, \( B = 0.5 \, \text{T} \)
- Velocity of the particles, \( v = 6 \times 10^{4} \, \text{m/s} \)
- Distances from the incident beam where particles A and B emerge: \( d_A = 3 \, \text{cm} = 0.03 \, \text{m} \) and \( d_B = 3.5 \, \text{cm} = 0.035 \, \text{m} \)

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