A straight wire carrying current of 1 A is suspended in a magnetic field. If the length and mass of the wire are 50 cm and 500 g respectively, what should be the magnitude of the magnetic field, so that it stays in equilibrium? Take ` g = 10 m//s^(2)`.

Explanation

To find the magnitude of the magnetic field required for the straight wire carrying a current of 1 A to stay in equilibrium, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Forces Acting on the Wire**:
The wire experiences two forces:
- The downward gravitational force (weight) due to its mass.
- The upward magnetic force due to the magnetic field.
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