A current carrying wire A is carrying current of 10 A from east to west and is fixed. Another wire B of maas 5 g, length 2 m and carrying a current 20 A is placed below the wire such that it remains suspended due to the magnetic force. Find the position of wire B and also indicate the direction of current in B. Take `g = 10 m//s^(2)`.

Explanation

To solve the problem, we need to analyze the forces acting on wire B due to the magnetic field created by wire A, and then find the position of wire B such that it remains suspended.

### Step-by-Step Solution:

1. **Identify the Forces Acting on Wire B**:
- Wire B has a mass \( m = 5 \, \text{g} = 0.005 \, \text{kg} \).
- The weight of wire B is given by \( W = m \cdot g = 0.005 \, \text{kg} \cdot 10 \, \text{m/s}^2 = 0.05 \, \text{N} \).
- For wire B to remain suspended, the magnetic force acting on it must equal its weight: \( F_B = W \).
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