A solenoid made up of copper wire consists of 400 turns and carries a current of 5 A. If length of the solenoid is 0.5 m and has a radius of 2 cm, find the magnitude of the magnetic field inside the solenoid.

Explanation

To find the magnitude of the magnetic field inside the solenoid, we can use the formula for the magnetic field inside a long solenoid:

\[ B = \mu_0 \cdot n \cdot I \]

Where:
- \( B \) is the magnetic field inside the solenoid,
- \( \mu_0 \) is the permeability of free space, approximately \( 4\pi \times 10^{-7} \, \text{T m/A} \),
- \( n \) is the number of turns per unit length of the solenoid,
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