A circular coil of wire consisting of 100 turns, each of radius `8.0` cm carries a current of` 0.40` A. What is the magnitude of the magnetic field B at the centre of the coil?

Explanation

To find the magnitude of the magnetic field \( B \) at the center of a circular coil, we can use the formula:

\[ B = \frac{\mu_0 N I}{2R} \]

where:
- \( \mu_0 \) is the permeability of free space, approximately \( 4\pi \times 10^{-7} \, \text{T m/A} \)
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