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A square coil of side 10 cm consists of ...

A square coil of side 10 cm consists of 20 turns and carries a current of 12A. The coil is suspended vertically and the normal to the plane makes an angle of `30^(@)` with the direction of uniform magnetic field of 0.8 T. The torque acting on the coil is

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The orientation of coil with respect to the mametic field is shown below:

The magnitude of torque acting on the coil of sidel and number of turns n, due to current I flowing through it is given by:
`tau = n I AB sin theta`
Here, ` l = 10 cm = 10^(-1) m`
` :. " Area of coil " , A = l^(2) =10^(-2) m^(2)`
` n = 20 , theta = 30^(@) , B = 0.80T`
` I = 12 A`
` rArr " " tau = 20 xx 12 xx 10^(-2) xx 0.8 xx sin 30^(@)`
` = 0.96 N m approx 1 N m`
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