In a chamber, a uniform magnetic field of `6.5 G (1 G = 10^(-4)T)` is maintained. An electron is shot into the field with a speed of `4.8 xx 10^(6) ms^(-1)` normal to the field. Explain why the path of the electron is a circle. Determine the radius of the circular orbit. `(e = 1.6 xx 10^(-19) C, m_(e) = 9.1 xx 10^(-31) kg)`.

Explanation

To solve the problem, we will follow these steps:

### Step 1: Understand the Motion of the Electron in a Magnetic Field
When a charged particle, such as an electron, moves through a magnetic field, it experiences a magnetic force that acts perpendicular to both the velocity of the particle and the direction of the magnetic field. This magnetic force acts as a centripetal force, causing the particle to move in a circular path.

### Step 2: Identify the Given Values
- Magnetic field strength, \( B = 6.5 \, \text{G} = 6.5 \times 10^{-4} \, \text{T} \)
- Speed of the electron, \( v = 4.8 \times 10^{6} \, \text{m/s} \)
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